In Fig. 6.35, ∆ ODC ~ ∆ OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB. Table of ContentsIn Fig. 6.35, ∆ ODC ~ ∆ OBA, ∠BOC = 125° and ∠CDO = 70°. Find ∠DOC, ∠DCO and ∠OAB.<Select SpecificallyGivenSolution:Tags: CBSE Solution Next Sides AB and BC and median AD of s triangle ABC are respectively proportional to sides PQ and QR and median PM of ∆ PQR. Show that ∆ ABC ~ ∆ PQR. Leave a Reply Cancel replyCommentEnter your name or username to commentEnter your email address to commentEnter your website URL (optional) Save my name, email, and website in this browser for the next time I comment. Sign me up for the newsletter!